Vectors will set you FREE! Here we change the straight, fixed in space basis, I, J K into a set, two of which move in a plane.
Vectors for Circular Motion Motion of a mass at constant speed constrained by forces to follow a circular path is kinematically described by the circle radius, and system vectors - position, velocity and acceleration.
The graphic shows the geometry with positive change of angle, θ(t) and d(θ(t))/dt being counter-clockwise. We use the I, J vector basis in our development. Position, in terms of the I - J basis is:
P(t) = r [cos( θ(t) )I + sin( θ(t) )J]
Two derivatives are taken to yield successively the velocity vector, V(t), and A(t), the acceleration vector. Each is written in a "magnitude times unit vector" form where the unit vectors, I and J are fixed in direction.
The above is correct in terms of the constant vector basis: I and J. Problems can be solved with this set - just as they are. However, these results can be used to confirm a simpler, less writing-intensive way of representing P(t), V(t) and A(t).
Compare the directions (unit vector parts) of the vectors, V and A with that of the initial unit vector, the direction of P. Immediately we see the direction of A is opposite the direction of P. Using a simple sketch, we see the direction of velocity, V is perpendicular to the direction of P, and directed toward increasing angle, θ. Thus we define er(t), and eθ(t).
The graphic representation of the unit vectors with analytic statements of position, velocity and acceleration vectors are shown.
P(t) = r er(t)
V(t) = r(dθ/dt)eθ(t)
A(t) = - r (dθ/dt)2 er(t)
Extension of this idea to apply to non-circular motion, that is for a radius that varies in time, r = r(t), follows easily since the radius is a scalar. The new vector basis described here is:
er(t), eθ(t) and K, (when needed).